$$ \left( P + \sqrt{K^2 - Q^2 + 2 Q y - y^2} - \frac{W}{2} \right)^2 $$ $$ = -(y + R - H)^2 + R^2 $$
এই ইকুয়েশন solve করতে করতে অবস্থা খারাপ।
$$
c^2 = a^2 + b^2 - 2ab \cos(\gamma)
$$
where:
$$
\begin{align*}
c & : \text{third side length} \\
a & : \text{first side length} \\
b & : \text{second side length} \\
\gamma & : \text{angle opposite third side}
\end{align*}
$$
$$
\text{Area}(\triangle) = \frac{1}{2} \cdot a \cdot b \cdot \sin(C)
$$
where:
$$
\begin{align*}
\text{Area}(\triangle) & : \text{Area of the triangle} \\
a & : \text{Length of side } a \\
b & : \text{Length of side } b \\
C & : \text{Angle opposite side } c
\end{align*}
$$
\[
A = \sqrt{s \cdot (s - a) \cdot (s - b) \cdot (s - c)}
\]
where \(s\) is the semi-perimeter, calculated as:
\[
s = \frac{a + b + c}{2}
\]